SOLUTION TO A SIMPLE PIPE NETWORK DISTRIBUTION PROBLEM USING
HARDY CROSS METHOD
- The method suggests that the flow in each pipe in magnitude and direction is to be initially ASSUMED in such a way that the principle of continuity is satisfied at each junction
- A correction to the assumed flows is computed successively for each pipe loop in the network until the correction is reduced to an acceptable magnitude. (Normally two iterations are sufficient)
- According to the principle of continuity the inflow at any junction is equal to the outflow at that junction
- As the method involves balancing quantities of inflow and outflow at each junction, it is also called quantity balance method
- Value of 'x' in Hardy-Cross method is assumed to be 1.85 for 'Hazen-William's' formula and 2 for Darcy-Weisbach formula.
- Minor losses are generally neglected
- The system should be divided into two or more loops such that each pipe in the network is included in at-least one loop
SUMMARIZING THE HARDY CROSS METHOD
- Assume any internally consistent distribution of flow
- Compute head loss in each pipe (clockwise flows are positive and produce positive head loss and vice versa)
- Paying attention to sign, compute the total head loss around each loop is computed.
- Compute the total head loss around each loop regardless of sign
- Apply corrections to the flow in each pipe
No comments:
Post a Comment